Gegeben  \ ist:  \
Gleichseitiges \ Dreieck \ mit \ \rho =1.5cm

Die \ Lösung \ ist: \ Δ ABC

M_I = (2.7, -0.82)
c = Circle(M_I, 1.5)
P = Point(c)
a = Line(P, M_I)
S = Intersect(c, a, 2)
b = OrthogonalLine(S, a)
Q = Point(b)
R = Rotate(S, 60°, Q)
α = Angle(S, Q, R)
d = Ray(Q, R)
e = OrthogonalLine(M_I, d)
T = Intersect(c, e, 2)
f = Line(T, d)
A = Intersect(b, f)
C = Intersect(a, f)
B = Rotate(A, 60°, C)
γ = Angle(A, C, B)
g = Ray(C, B)
Vieleck1, c_1, a_1, b_1 = Polygon(A, B, C)